January 2012 Sudoku Solution


February 2012 Sudoku Solution

January 2012 Math Solution
Four times the number of Coles was equal to nine times the number of Mias.  Three times the number of Mias exceeded the number of Gavins by four.  The total number of Coles, Mias, and Gavins was seventy-one.  How many were Coles, how many were Mias, and how many were Gavins?

Eq. 1: C + M + G = 71
Eq. 2: 3M - 4 = G
Eq. 3: 4C = 9M

C + (3M - 4) + M= 71 --> 4M + C = 75 --> 4M + (9M / 4) = 75
25M = 300 --> 12 Mias

3(12) - 4 = G --> 32 Gavins

C + 12 + 32 = 71 --> 27 Coles

February 2012 Math SolutionA chocolate bar, 224 inches in length, is broken into 3 pieces. Twice the length of the left-most piece is 9 inches less than three times the length of the middle piece. Twice the length of the middle piece is 8 inches less than the length of the right-most piece. HOW LONG IS EACH PIECE?

Eq. 1: L + M + R = 224
Eq. 2: 2M + 8 = R
Eq. 3: 2L + 9 = 3M

L + M + (2M + 8) = 224
L + 3M = 216 --> L + (2L + 9) = 216
L = the Left-most piece is 69 inches

2(69) + 9 = 3M --> 147 = 3M --> the Middle piece is 49 inches

69 + 49 + R = 224 --> the Right-most piece is 106 inches

<-- January 2012 Artwork
Medusa Head (sculpture) by William McVey (1905-). 6 ft. x 6 ft. x 18 in. Cast Stone. Formerly located at Medusa Cement Company in Cleveland Heights, Ohio. Relocated in 2001 to Woodland Gardens at the Cleveland Botanical Gardens in Cleveland, Ohio.

<-- February 2012 Display
Ice harvesting on Sandusky Bay display at the Maritime Museum of Sandusky. Sandusky, Ohio