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March 2010
Sudoku Solution
March 2010 Math Problem Solution
The perimeter of a rectangle is 56 cm. Its length is 4 cm more than 3 times its width. WHAT IS ITS LENGTH?
2L + 2W = 56
L = 3W + 4
2(3W + 4) + 2W = 56
6W + 8 + 2W = 56
8W + 8 = 56
8W = 48
W = 6
L = 3(6) + 4
L = 22
The length of the rectangle is 22 cm.
March 2010 Art Answer
James Abbott McNeill Whistler (American, 1834-1903) Limehouse. Etching, 1859. 1912.1195
Toledo Museum of Art
Toledo, OH
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